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Question

The compressibility factor for nitrogen at 330 K and 800 atm is 1.90 and at 570 K and 200 atm is 1.10. A certain mass of N2 occupies a volume of 1 dm3 at 330 K and 800 atm. Calculate the volume occupied by same quantity of N2 gas at 750 K and 200 atm.


A

1 L

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B

2 L

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C

3 L

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D

4 L

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Solution

The correct option is D

4 L


Z=PVnRT1.90=1×800n×R×330

n = 1×8001.90×R×330

Z = 1.10 = V×200n×R×570

1.10 = V×200×1.90×R×330800×R×570

V = 4L


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