The compressibility factor of a gas is greater than unity at STP. Therefore :

V_{m} > 22.4 L

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V_{m} < 22.4 L

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V_{m} = 22.4 L

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The gas will become less liquefiable

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Solution

The correct options are
A $V_{m} > 22.4 L$
D The gas will become less liquefiable
$Z_{r e a l g a s} > 1$
$∴ V_{m} > 22.4 L$ $(B e c a u s e V_{i d e a l} = 22.4 L)$
Hence, when volume is higher, the gases are far apart and, therefore, difficult to liquefy.

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The compressibility factor of a gas is less than 1 at STP. Its molar volume $V_{m}$ will be:

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