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Standard XII

Chemistry

Graham's Law of Effusion

The compressi...

Question

The compressibility factor of $N_{2}$ at 330K and 800 atm is 1.90 and at 570K and 200 atm is 1.10. A certain mass of $N_{2}$ occupies a volume of $1 {d m}^{3}$ at 330K and 800 atm. Calculate the volume of $N_{2}$ gas at 570 K and 200 atm:

6 liters

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3 liters

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2 liters

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4 liters

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Solution

The correct option is C 4 liters
Ideal gas equation:

$P V = n R T$

Compressibility factor,

$Z = \frac{{P V}_{M}}{n R T}$

As given,

$\Rightarrow 1.9 = \frac{1 \times 800}{n \times R \times 330}$

$n = \frac{1 \times 800}{1.9 R \times 330}$

Using this we can calculate the volume.

$Z = 1.1 = \frac{V \times 200}{n R \times 570}$

$V = 4 L$

So volume of $N_{2}$ gas at 570 K and 200 atm = 4 litre

Hence, the correct option is $D$

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Similar questions

Q. The compressibility factor of

N_{2}

at & 800 atm is 1.90 and at 570K & 200 atm is 1.10. A certain mass if

N_{2}

occupies a volume of

{1 d m}^{3}

at 330K and 800 atm. Calculate the volume of

N_{2}

gas at 570K and 200 atm.

Q. The compressibilty factor of

N_{2}

at 330K & 800 atm is 1.90 and at 570K & 200 atm is 1.10. A certain mass of

N_{2}

occupies a volume of

1 d m^{3}

at 330K and 800 atm. Calculate the volume of

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Q. The compressibility factor of nitrogen at 330 K and 800 atm is 1.90 and at 570 K and 200 atm is 1.10. A certain mass of

N_{2}

occupies a volume of 1

d m^{3}

at 330 K and 800 atm. Calculate the volume occupied by the same quantity of

N_{2}

gas at

570 K

and

200 atm

Q. The compressibility factor of nitrogen at 330 K and 800 atm is 1.90 and at 570 K and 200 atm is 1.10. A certain mass of

N_{2}

occupies a volume of 1

d m^{3}

at 330 K and 800 atm. Calculate the volume occupied by the same quantity of

N_{2}

gas at

570 K

and

200 atm

Q. The compressibilty factor of

N_{2}

at 330 K & 800 atm is 1.90 and at 570 K & 200 atm is 1.10 A certain mass of

N_{2}

occupies a volume of 1

d m^{3}

at 330 K and 800 atm. Calculate the volume of

N_{2}

gas at 570 K and 200 atm :

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The compressibility factor of N2 at 330K and 800 atm is 1.90 and at 570K and 200 atm is 1.10. A certain mass of N2 occupies a volume of 1dm3 at 330K and 800 atm. Calculate the volume of N2 gas at 570 K and 200 atm:

The correct option is C 4 litersIdeal gas equation:PV=nRTCompressibility factor,Z=PVMnRTAs given,⇒1.9=1×800n×R×330n=1×8001.9R×330Using this we can calculate the volume.Z=1.1=V×200nR×570V=4 LSo volume of N2 gas at 570 K and 200 atm = 4 litreHence, the correct option is D

The compressibility factor of $N_{2}$ at 330K and 800 atm is 1.90 and at 570K and 200 atm is 1.10. A certain mass of $N_{2}$ occupies a volume of $1 {d m}^{3}$ at 330K and 800 atm. Calculate the volume of $N_{2}$ gas at 570 K and 200 atm: