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Standard XII

Chemistry

Compressibility Factor

The compressi...

Question

The compressibility factor of $N_{2}$ at & 800 atm is 1.90 and at 570K & 200 atm is 1.10. A certain mass if $N_{2}$ occupies a volume of ${1 d m}^{3}$ at 330K and 800 atm. Calculate the volume of $N_{2}$ gas at 570K and 200 atm.

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Solution

$n = \frac{P V}{z R T}$
$\Rightarrow^{n} 330 K = \frac{1 \times 800}{1.9 \times R \times 330} ⟶ (1)$ $z = 1.9$
$\Rightarrow^{n} 570 K = \frac{V \times 200}{1.1 \times R \times 570} ⟶ (2)$ $z = 1.1$
By equalizing (1) & (2)
$V = 4 L$

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Similar questions

Q. The compressibility factor of

N_{2}

at 330K and 800 atm is 1.90 and at 570K and 200 atm is 1.10. A certain mass of

N_{2}

occupies a volume of

1 {d m}^{3}

at 330K and 800 atm. Calculate the volume of

N_{2}

gas at 570 K and 200 atm:

Q. The compressibilty factor of

N_{2}

at 330K & 800 atm is 1.90 and at 570K & 200 atm is 1.10. A certain mass of

N_{2}

occupies a volume of

1 d m^{3}

at 330K and 800 atm. Calculate the volume of

N_{2}

gas at 570K and 200 atm:

Q. The compressibility factor of nitrogen at 330 K and 800 atm is 1.90 and at 570 K and 200 atm is 1.10. A certain mass of

N_{2}

occupies a volume of 1

d m^{3}

at 330 K and 800 atm. Calculate the volume occupied by the same quantity of

N_{2}

gas at

570 K

and

200 atm

The compressibility factor for nitrogen at 330 K and 800 atm is 1.90 and at 570 K and 200 atm is 1.10. A certain mass of $N_{2}$ occupies a volume of 1 $d m^{3}$ at 330 K and 800 atm. Calculate the volume occupied by same quantity of $N_{2}$ gas at 750 K and 200 atm.

Q. The compressibilty factor of

N_{2}

at 330 K & 800 atm is 1.90 and at 570 K & 200 atm is 1.10 A certain mass of

N_{2}

occupies a volume of 1

d m^{3}

at 330 K and 800 atm. Calculate the volume of

N_{2}

gas at 570 K and 200 atm :

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The compressibility factor of N2 at & 800 atm is 1.90 and at 570K & 200 atm is 1.10. A certain mass if N2 occupies a volume of 1dm3 at 330K and 800 atm. Calculate the volume of N2 gas at 570K and 200 atm.

n=PVzRT⇒n330K=1×8001.9×R×330⟶(1) z=1.9⇒n570K=V×2001.1×R×570⟶(2) z=1.1By equalizing (1) & (2)V=4L

The compressibility factor of $N_{2}$ at & 800 atm is 1.90 and at 570K & 200 atm is 1.10. A certain mass if $N_{2}$ occupies a volume of ${1 d m}^{3}$ at 330K and 800 atm. Calculate the volume of $N_{2}$ gas at 570K and 200 atm.

$n = \frac{P V}{z R T}$
$\Rightarrow^{n} 330 K = \frac{1 \times 800}{1.9 \times R \times 330} ⟶ (1)$ $z = 1.9$
$\Rightarrow^{n} 570 K = \frac{V \times 200}{1.1 \times R \times 570} ⟶ (2)$ $z = 1.1$
By equalizing (1) & (2)
$V = 4 L$