Question

The compressibility factor, $Z=\frac{PV}{RT}$ for $1\text{mole}$ of a real gas is greater than unity at a pressure of $1\text{atm}$ and $273.15\text{K}$. The molar volume of the gas at STP will be:

• A. Less than $22.4\text{L}$
• B. Greater than $22.4\text{L}$
• C. Equal to $22.4\text{L}$
• D. None of these

Answer 1

The correct option is B Greater than $22.4\text{L}$

$Z=\frac{V_{\text{real}}}{V_{\text{ideal}}}$
Given, z > 1
$\Rightarrow V_{\text{real}}>V_{\text{ideal}}$
Hence, the gas will have volume more than $22.4\text{L}$.