The compressibility of a gas is less than unity at STP. Therefore, its molar volume is
A
Vm>22.4 L
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B
Vm<22.4 L
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C
Vm=22.4 L
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D
Vm=44.8 L
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Solution
The correct option is BVm<22.4 L Given: Z<1
as compressibility factor (Z) is given as Z=Vm,realVm,ideal ∴Vm,realVm,ideal<1 ⇒Vm,real22.4 L<1
because Molar volume of ideal gas at STP =22.4 L ⇒Vm,real<22.4 L