Question

The compressibility of a gas is less than unity at $STP$. Therefore,

• A. $V_m>22.4L$
• B. $V_m<22.4L$
• C. $V_m=22.4L$
• D. $V_m=44.8L$

Answer 1

Answer: (B)

$V_m<22.4L$

The compressibility factor '$z$' is the ratio of the actual volume of the gas due to non ideal behaviour to the volume of the gas due to ideal behaviour.
$Z=\frac{V_{real}}{V_{ideal}}$.
But $Z<1$.
Hence, $\frac{V_{real}}{V_{ideal}}$ or $V_{real}<V_{ideal}$.
At $STP$, 1 mole of ideal gas occupies a volume of 22.4 $L$.
Hence, at $STP$, 1 mole of a real gas will occupy a volume less than 22.4 $L$.