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Byju's Answer
Standard XII
Chemistry
Compressibility Factor
The compressi...
Question
The compressiblity factor for a real gas at high pressure is:
A
1
+
R
T
P
b
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B
1
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C
1
+
P
b
R
T
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D
1
−
P
b
R
T
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Solution
The correct option is
C
1
+
P
b
R
T
The van der Waals' equation is given as
(
P
+
a
V
2
)
(
V
−
b
)
=
R
T
(for 1 mol of gas)
At high pressure,
a
V
2
term can be neglected, since P is large.
P
V
−
P
b
=
R
T
or
P
V
=
R
T
+
P
b
P
V
R
T
=
1
+
P
b
R
T
Z
=
1
+
P
b
R
T
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Similar questions
Q.
The compressibility factors for 1 mole of real gases at low pressure, high pressure and that of gases of very low molar masses are
Z
1
,
Z
2
and
Z
3
. These are
Q.
The compressiblity factor (Z) for 1 mole of a real gas at low pressure can be written as:
Q.
At low pressures, the van der Waals equation is written as
[
P
+
a
V
2
]
V
=
R
T
. The compressiblity factor of the gas is:
Q.
If
Z
is a compresibility factor, van der waals equation at low pressure can be written as:
Q.
For the reaction
C
O
(
g
)
+
(
1
/
2
)
O
2
(
g
)
⇌
C
O
2
(
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)
,
K
p
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K
c
is
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Compressibility Factor
Standard XII Chemistry
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