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Question

The compressiblity factor for nitrogen at 330 K and 800 atm is 1.90 and at 570 K and 200 atm is 1.10. A certain mass of N2 occupies a volume of 1 dm3 at 330 K and 800 atm. Calculate volume occupied by same quantity of N2 gas at 570 K and 200 atm:

A
1 L
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B
2 L
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C
3 L
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D
4 L
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Solution

The correct option is D 4 L
Z=PVnRT;1.90=1×800n×R×330n=1×8001.90×R×330Z=1.10=V×200n×R×5701.10=V×200×1.90×R×330800×R×570
V=4 L

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