The compressiblity factor for nitrogen at 330K and 800atm is 1.90 and at 570K and 200atm is 1.10. A certain mass of N2 occupies a volume of 1dm3 at 330K and 800atm. Calculate volume occupied by same quantity of N2 gas at 570K and 200atm:
A
1L
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B
2L
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C
3L
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D
4L
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Solution
The correct option is D4L Z=PVnRT;⇒1.90=1×800n×R×330⇒n=1×8001.90×R×330Z=1.10=V×200n×R×570⇒1.10=V×200×1.90×R×330800×R×570 ⇒V=4L