Question

The compressiblity of a gas is less than unit at STP. Therefore, molar ($V_m$) of a real gas is given by

• A. $V_m>22.4$ litre
• B. $V_m<22.4$ litre
• C. $V_m=22.4$ litre
• D. $V_m=44.8$ litre

Answer 1

The correct option is B $V_m<22.4$ litre

It is given that compressibility factor is less than 1.

We have to find the relation between $V_{\mathrm{Re}al}$ and $V_{Ideal}$ in order to solve the question.

Now, we know that compressibility factor$=\frac{V_{\mathrm{Re}al}}{V_{Ideal}}$ which is given to be less than 1.

Hence, $V_{\mathrm{Re}al}<V_{Ideal}$

Since we know that $V_{Ideal}=22.4L$

$\therefore V_{Ideal}<22.4L$$\Rightarrow V_m<22.4L$

Hence, option (b) is correct.