The correct option is A 4×10−12
Given, [Ag+]=2.0×10−4
The equilibrium between the undissolved solid Ag2CrO4(s) and the ions in a saturated solution can be represented by the solution
Ag2CrO4(s)⇌2Ag+(aq)+CrO2−4(aq)t=teq c−s 2s s
Ksp=[Ag+]2[CrO2−4]
Also, [CrO2−4]=12[Ag+]
[Ag+]=2s=2.0×10−4Ms=1.0×10−4M
∴[CrO2−4]=s=1×10−4M
So, Ksp=[Ag+]2[CrO2−4]Ksp=(2.0×10−4)2×(1.0×10−4)
Ksp=4×10−12