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Question

The concentration of [Ag+] ion in a saturated solution of sparingly soluble salt Ag2CrO4 at equilibrium is 2.0×104. Calculate the value of Ksp for Ag2CrO4?

A
4×1012
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B
2×106
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C
2×106
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D
2×1011
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Solution

The correct option is A 4×1012
Given, [Ag+]=2.0×104
The equilibrium between the undissolved solid Ag2CrO4(s) and the ions in a saturated solution can be represented by the solution
Ag2CrO4(s)2Ag+(aq)+CrO24(aq)t=teq cs 2s s

Ksp=[Ag+]2[CrO24]
Also, [CrO24]=12[Ag+]
[Ag+]=2s=2.0×104Ms=1.0×104M

[CrO24]=s=1×104M
So, Ksp=[Ag+]2[CrO24]Ksp=(2.0×104)2×(1.0×104)
Ksp=4×1012

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