The concentration of chloride ion, in molarity, in a solution containing $10.56$ g $B a C l_{2} .8 H_{2} O$ per litre of solution is $(B a = 137)$ :

0.06

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0.07

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0.18

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0.21

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Solution

The correct option is A $0.06$ M
The molar mass of $B a C l_{2} .8 H_{2} O$ is $352.23$ g/mol.

$10.56$ g of $B a C l_{2} .8 H_{2} O$ corresponds to $\frac{10.56}{352.23} = 0.03$ moles. It is present in $1$ L of solution.

Hence, the molarity of $B a C l_{2} .8 H_{2} O$ is $0.03$ M.

$1$ mole of $B a C l_{2} .8 H_{2} O$ gives two moles of chloride ions. Hence, the molarity of chloride ions is $2 \times 0.03 = 0.06 M$ .

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