The concentration of hydroxide ions ( $O H^{-}$ ) is affected when an excess base is dissolved in a solution of sodium hydroxide. The concentration of base in the new solution will:

increase

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decrease

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remain same

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none of these

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Solution

The correct option is A increase
The concentration of sodium hydroxide ions increases as more of $N a O H$ solution is added as base. More hydroxide ions means more concentration of hydrogen ions is needed to neutralize this base so the pH of the solution increases.

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Similar questions

How is the concentration of hydroxide ions (OH⁻) affected when excess base is dissolved in a solution of sodium hydroxide?

({OH}^{-})

O H^{-}

0.05

0.001

O H^{-}

K_{b} (N H_{4} O H) = 1.8 \times 10^{- 5}

5

0.01 M

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