Question

The concentration of $\left[H^{+}\right]$ in a sample soft drink is $3\times 10^{-3}M$. What is its $pH.$ $(log3=0.48)$

Answer 1

Formula for $pH=-log\left[H^{+}\right]$
given $\left[H^{+}\right]=3\times 10^{-3}M$
$\therefore pH=-log(3\times 10^{-3})=-[log3+log10^{-3}]=-[0.48+(-3)]=-[-2.52]pH=2.52$