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Question
The concentration of [H+] in a sample soft drink is 3×10−3M. What is its pH. (log3=0.48)
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Solution
Formula for pH=−log[H+]
given [H+]=3×10−3M
∴pH=−log(3×10−3)=−[log3+log10−3]=−[0.48+(−3)]=−[−2.52]pH=2.52
given [H+]=3×10−3M
∴pH=−log(3×10−3)=−[log3+log10−3]=−[0.48+(−3)]=−[−2.52]pH=2.52
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