The concentration of minority carriers in an extrinsic semiconductor under equilibrium is

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Solution

Ans : (b)

As per mass action law,

$n p = n_{i}^{2}$
$n_{i} = c o n s t a n t$
For n-type $p$ is minority carrier concentration
$p = \frac{n_{i}^{2}}{n}$
$p \propto \frac{1}{n}$

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An intrinsic carrier concentration of a p-type semiconductor is 1 \times 10^{10} / c m^{3} and the majority carrier concentration is 1 \times 10^{18} / c m^{3} . Then minority carrier concentration is (Assume the p-type semiconductor is under thermal equilibrium)

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