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Raoult's Law

the concentra...

Question

the concentration of NH_4+ IONS in an aqueous solution which is 0.02M NH3 & 0.01M KOH would be: kb=1.8×10^{-5

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Solution

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[{N H}_{4}^{+}]

{N H}_{3}

K_{b} = {1.8 \times 10}^{- 5}

N H_{4}^{+}

0.02 M N H_{3}

0.01 M K O H

(K_{b}

N H_{3} = 1.8 \times 10^{- 5} M)

K_{a}

H A s c,

5 \times 10^{- 5}

{A s c}^{-}

0.02 M

K_{a}

(N H {_{4}}^{+})

5.6 \times 10^{- 10}

K_{b}

N H_{3} = 1.8 \times 10^{- 5}

0.01 M

R N H_{2}

(K_{b} = 2 \times 10^{- 6})

10^{- 4} M N a O H

O H^{-}

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