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Lewis Theory

The concentra...

Question

The concentrations of $C l^{-} & C r O_{4}^{2 -}$ in a solution are $0.1 M & 10^{- 4} M$ respectively. If solid $A g N O_{3}$ is gradually
added to this solution, what will be the concentration of $C l^{-}$ when $A g_{2} C r O_{4}$ begins to precipitate? $[K_{s p} (A g C l) = 10^{- 10} M^{2}; K_{s p} (A g_{2} C r O_{4}) = 10^{- 12} M^{3}]$

A

10^{- 6} M

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B

10^{- 4} M

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C

10^{- 5} M

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D

10^{- 9} M

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Solution

The correct option is A $10^{- 6} M$
$A g_{2} C r O_{4_{(s)}} ⇌ 2 A g^{+} + C r O_{4}^{2 -} k_{s p} A g_{2} C r O_{4} = [A g^{+}]^{2} [C r O_{4}^{2 -}] 10^{- 12} = [A g^{+}]^{2} [10^{- 4}] ∴ [A g^{+}] = 10^{- 4} M A g C l_{(s)} ⇌ A g^{+} + C l^{-} k_{s p} A g C l = [A g^{+}] [C l^{-}] 10^{- 10} = [10^{- 4}] [C l^{-}] \Rightarrow [C l^{-}] = 10^{- 6} M$

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Similar questions

Q. A solution is made of

0.1 M

C l^{-}

10^{- 4} M C r O_{4}^{2 -}

A g N O_{3}

is gradually added to this solution, then what will be the concentration of

C l^{-}

A g_{2} C r O_{4}

begins to precipitate?

[K_{s p} (A g C l) = 10^{- 10} M^{2}; K_{s p} (A g_{2} C r O_{4}) = 10^{- 12} M^{3}]

Q. A solution contains

0.1 M

{C l}^{-}

0.001 M

C r O_{4}^{2 -}

A g {N O}_{3}

is gradually added to this solution, which will precipitate first,

A g C l

{A g}_{2} C r O_{4}

? Assume that the addition causes no change in volume. Given

K_{s p} A g C l = 1.7 \times 10^{- 10} M^{2}

K_{s p} {A g}_{2} C r O_{4} = 1.79 \times 10^{- 12} M^{3}

What percent of

{C l}^{-}

remains in the solution when

C r O_{4}^{2 -}

starts precipitating?

A g N O_{3}

is added to a solution which is

0.1 M

C l^{-}

0.1 M

C r O_{4}^{2 -}

K_{s p}

A g C l

A g_{2} C r O_{4}

1.7 \times 10^{- 10}

1.9 \times 10^{- 12}

respectively. Find the minimum concentration of

C l^{-}

A g_{2} C r O_{4}

starts precipitating.

A g N O_{3}

is added to a solution which is

0.1 M

C l^{-}

0.1 M

C r O_{4}^{2 -}

K_{s p}

A g C l

A g_{2} C r O_{4}

1.7 \times 10^{- 10}

1.9 \times 10^{- 12}

respectively. Find the minimum concentration of

C l^{-}

A g_{2} C r O_{4}

starts precipitating.

A g N O_{3}

is gradually added to a solution which is

0.01 M

C l^{-}

0.01 M

C O_{3}^{2 -}

K_{s p} A g C l = 1.8 \times 10^{- 10} (m o l L^{- 1})^{2}

K_{s p} A g_{2} C O_{3} = 4 \times 10^{- 12} (m o l L^{- 1})^{3}

. The concentration of

C l^{-}

A g_{2} C O_{3}

starts precipitating is:

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