Question

The condition called standard temperature and pressure (STP) for a gas is defined as temperature of $0^{\circ }C=273.15K$ and a pressure of 1 atm = $1.013\times {10}^5$ Pa. If you want to keep a mole of an ideal gas in your room at STP, how big a container do you need?

• A. $44.4L$
• B. $12.4L$
• C. $22.4L$
• D. $11.2L$

Answer 1

Answer: (C)

$22.4L$

From the ideal gas equation $PV=nRT$,

At STP,

$\left(1.013X{10}^5\right)V=1\left(8.314\right)\left(273.15\right)$

$V=\frac{2270.97}{1.013X{10}^5}=22.4X{10}^{-3}{m}^3=22.4L$

Answer is $22.4L$