The condition for y=ax4+bx3+cx2+dx+e to have points of inflection is
A
b2−4ac>0
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B
3b2−8ac=0
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C
3b2−8ac>0
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D
3b2−8ac<0
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Solution
The correct option is C3b2−8ac>0 f′′(x)=0 for inflection point. f′(x)=4ax3+3bx2+2cx f′′(x)=12ax2+6bx+2c=0 Roots of this equation will be x=−3b±√9b2−24ac12a So 9b2−24ac>0 3b2−8ac>0