Question

The condition for obtaining secondary maxima in the diffraction pattern due to single slit is

• A. $a\sin \theta =n\lambda$
• B. $a\sin \theta =(2n-1)\frac{\lambda }{2}$
• C. $a\sin \theta =(2n-1)\lambda$
• D. $a\sin \theta =\frac{n\lambda }{2}$

Answer 1

The correct option is B $a\sin \theta =(2n-1)\frac{\lambda }{2}$

In the diffraction pattern due to single slit, condition for secondary maxima is
$a\sin \theta =(2n-1)\frac{\lambda }{2}$ where $n=2,3,4,....$.