The condition for the points (x,y), (-2,2) and (3,1) to be collinear is

x+5y=8

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x+5y=6

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5x+y=8

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5x+y=6

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Solution

The correct option is A x+5y=8
$1 / 2 (x (2 - 1) - 1 (1 - y) + 3 (y - 2)) = 0$
or x + 5y = 8

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Similar questions

Solve for x and y:

$x + \frac{6}{y} = 6, 3 x - \frac{8}{y} = 5 (y \neq 0) .$

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B (- 3, 4)

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8 x + 5 y \leq 40

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8 x + 5 y = 9

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