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Question

The condition for which the quadratic equation (p23p+2)x2+(p24)x+(p1)=0 will have a graph which is an upward opening parabola is

A
p(1,2)
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B
pR
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C
p(,1) (2,)
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D
p(,1) (2,)
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Solution

The correct option is D p(,1) (2,)
For f(x)=ax2+bx+c, the graph is an upward opening parabola when a>0.

Here we have f(x)=(p23p+2)x2+(p24)x+(p1)
So for an upward opening parabolic graph,
p23p+2>0
(p1)(p2)>0
So using wavy curve method, we get


p(,1) (2,)

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