CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
123
You visited us 123 times! Enjoying our articles? Unlock Full Access!
Question

The condition that f(x)=ax3+bx2+cx+d has no extreme value is

A
b2>3ac
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
b2=4ac
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
b2=3ac
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
b2<3ac
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D b2<3ac
f(x)=ax3+bx2+cx+d
f(x)=3ax2+2bx+c
For no extrema, f should have zero turning points, i.e. above quadratic have no real roots.
(2b)243ac<0
b2<3ac

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Extrema
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon