The condition that the straight line lx+my+n=0 touches the parabola x2=4ay is
A
bn=am2
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B
al2−mn=0
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C
ln=am2
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D
am=ln2
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Solution
The correct option is Bal2−mn=0 we can write lx+my+n=0 in from of y=Mx+c
So, my=−lx−n y=−lxm−nm
comparing with y=Mx+c M=−lm,c=−nm
For line to touch parabola x2=4ay, c=−aM2 ⇒al2=mn