The condition that two tangents to the parabola y2=4gx become normals to the circle x2+y2−2gx−2fy+c=0 is given by
Tangent of the given parabola with slope m is y=mx+gm
For it to be a normal to the given circle , it has to pass through the centre of it.
Hence (g,f) has to satisfy tangent equation of parabola.
⇒f=mg+gm
m2g−mf+g=0
Two tangents ⇒ the equation has two distinct real roots
which is possible when f2−4g2>0
⇒f2>4g2
Hence, option 'D' is correct.