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The conductance of a 0.0015 M aqueous solution of a weak monobasic acid was determined by using a conductivity cell consisting of platinized Pt electrodes. The distance between the electrodes is 120 cm with an area of cross section of 1cm2. The conductance of this solution was found to be 5×107S. The pH of the solution is 4. The value of limiting molar conductivity (Λm) of this weak monobasic acid in aqueous solution is Z×102Scm1mol1. The value of Z is___

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Solution

C=0.0015M l=120cm
G=5×107S a=1cm2
G=κ×al5×107=κ×1120κ=6×105Scm1Λcm=κ×1000M=6×105×10000.0015pH=4
[H+]=104=Cα=0.0015αα=1040.0015α=ΛcmΛom1040.0015=6×105×10000.0015ΛomΛom=6×102 Scm2mole1

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