Question

The conductivity of a solution containing $1.0g$ of anhydrous $Bac{l}_2$ in $200c{m}^3$ of the solution has been found to $0.0058Sc{m}^{-1}$.Calculate the moral conductivity and equivalent conductivity of the solution.

Answer 1

Concentration of solution =$\frac{1\times 1000}{208.23\times 200}$

= 0.02401

${\Lambda }_m=\frac{\kappa \times 1000}{c}$

= $\frac{0.0058\times 1000}{0,02401}$

${\Lambda }_m=240.65Sc{m}^{2}Mo{l}^{-}$

${\Lambda }_{eq}=\frac{{\Lambda }_m}{n-factor}$

${\Lambda }_{eq}=\frac{240.65}{2}$

= 120.325 $Sc{m}^{2}e{q}^{-}$