Question

The conductivity of an aqueous solution of a weak monoprotic acid is $0.000032oh{m}^{-1}c{m}^{-1}$ at a concentration 0.2M. If at this concentration, the degree of dissociation is 0.02, then the value of ${\lambda }_{\infty }$ (equivalent conductance at infinite dilution in $oh{m}^{-1}c{m}^2/eqt)$ is :

Answer 1

${\lambda }_m=\frac{0.000032}{0.2\times {10}^{-3}}$

$\alpha =0.02$

$\alpha =\frac{{\lambda }_m}{{\lambda }_{\infty }}$

So, ${\lambda }_{\infty }$ = $\frac{0.032\times 5}{0.02}=8$