Question

The conductor $AD$ moves to the right in a uniform magnetic field directed into the plane of the paper.

• A. The free electron in $AD$ will move toward $A$
• B. $D$d will acquire a positive potential with respect to $A$
• C. $A$ current will flow from $A$ to $D$ in $AD$ in closed loop
• D. The current in $AD$ flows from lower to higher potential
• E. answer required

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A The free electron in $AD$ will move toward $A$
B $D$d will acquire a positive potential with respect to $A$
C $A$ current will flow from $A$ to $D$ in $AD$ in closed loop
D The current in $AD$ flows from lower to higher potential

$E=(v\times B).l$

Therefore inside the rod, the electric field will have the direction from A to D.

Therefore negatively charged electron will move towards A.

This will cause the potential of A to decrease with respect to D.

Positive charge will flow from A to D along the electric field. So the direction of current in AD in closed loop is from A to D.

As D is at a higher potential, current in AD flows from lower(A) to higher potential(D)