The configuration 1s $^{2}$ 2s $^{2}$ 2p $^{5}$ 3s $^{1}$ shows the :

ground state of the fluorine atom

No worries! We‘ve got your back. Try BYJU‘S free classes today!

excited state of the fluorine atom

No worries! We‘ve got your back. Try BYJU‘S free classes today!

excited state of the neon atom

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

excited state of O

_{2}^{-}

ion

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D excited state of the neon atom
The configuration 1s $^{2}$ 2s $^{2}$ 2p $^{5}$ 3s $^{1}$ shows the excited state of the neon atom.
Total number of electrons $= 2 + 2 + 5 + 1 = 10$ . This is the atomic number of Ne.

Suggest Corrections

Similar questions

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}

C u

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{9}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1} 3 d^{10}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {3 d}^{3} {4 s}^{2}

1 s^{2} 2 s^{2} 2 p^{5} 3 s^{1}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

Join BYJU'S Learning Program