The configuration of the valence orbital of an element with atomic number 22 is :

3 d^{5} 4 s^{1}

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3 d^{2} 4 s^{2}

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4 s^{1} 4 p^{1}

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3 d^{2} 4 s^{1} 4 p^{1}

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Solution

The correct option is B $3 d^{2} 4 s^{2}$
For element with atomic number = 22
has electronic configuration: $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{2}$
thus valence shell configuration is: $3 d^{2} 4 s^{2}$

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