wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The conic represented by the equation 2xy+4x6y+17=0 is

A
an ellipse
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a pair of straight line
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a parabola
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a hyperbola
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D a hyperbola
On compairing the given equation with ax2+by2+2hxy+2gx+2fy+c=0, we get
a=b=0,c=17,g=2,f=3,h=1
Δ=abc+2fghaf2bg2ch2=290
and h2ab=10>0
Hence Δ0,h2>ab
So the given equation represents a hyperbola.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon