The correct option is C parabola
Given equations are x = t2+t+1 and y = t2−t+1.
x+y = 2t2+2 and x−y=2t
x+y = 2t2+2 ⇒2(x+y)=(2t)2+4⇒2(x+y)=(x−y)2+4⇒x2+y2−2xy−2x−2y+4=0
Here, a = 1, b = 1, h = -1, g = -1, f = -1, c = 4.
Now, △ = abc + 2fgh −af2−bg2−ch2⇒△ = −4≠0And h2=ab
So, the given equation represents a parabola.