The conjugate acid of ${N H_{2}}^{-}$ is:

N H_{4}^{+}

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N H_{3}

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N H_{2} O H

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N H^{-}

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Solution

The correct option is A $N H_{3}$
The conjugate acid of amide ion $(N H_{2}^{-})$ is ammonia, $N H_{3}$ .
When a proton is added to a base, we get conjugate acid.
${N H_{2}}^{-} + H^{+} \to N H_{3}$

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