The conjugate acid of $N H_{2}^{-}$ is $:$

N H_{4}^{-}

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N H_{3}

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N H_{2} O H

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N_{2} H_{4}

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Solution

The correct option is D $N H_{3}$
$N H_{2}^{-} + H_{2} O \to N H_{3} + O H^{-}$

Therefore, conjugate acid will be ammonia.

Hence, option $B$ is correct.

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