Question

The conjugate acid of $S_2{O}_3^{-2}$ is:

• A. $HS{O}_4^{-}$
• B. $H_{2}S{O}_4$
• C. $H_2{S}_2{O}_8$
• D. $H{S}_2{O}_3^{-}$

Answer 1

The correct option is D $H{S}_2{O}_3^{-}$

Adding one $H^{+}$ to anything gives you its conjugate acid.

Removing one $H^{+}$ gives you its conjugate base.

Conjugate Acid of $S_2{O}_3^{-2}$

$S_2{O}_3^{-2}+H^{+}\to H{S}_2{O}_3^{-1}$

Option D is correct.