The conjugate base of $H_{2} S O_{4}$ in the following reaction is:
$H_{2} S O_{4} + H_{2} O \to H_{3} O^{+} + H S O_{4}^{-}$

H_{2} O

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H S O_{4}^{-}

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H_{3} O^{+}

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S O_{4}^{- 2}

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Solution

The correct option is B $H S O_{4}^{-}$
Conjugate acid base pair differ by a single proton and base is one which accept proton,acid is which donates proton.

So conjugate base of the acid is one formed after the donation of proton by the acid.

So the conjugate base of $H_{2} S O_{4}$ is $H S O_{4}^{-}$ .

Option B is correct.

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Similar questions

Conjugate base of the following reaction is

Reaction:H2SO4 + H2O (reversibly giving)H3O^+ + HSO4^-

Ans gn:H3O^+ ,H2SO4

H_{2} S O_{4} (a q) + H_{2} O (l) ⇌ H_{3} O^{+} (a q) + H S O_{4}^{-} (a q)

H C_{2} H_{3} O_{2} (a q) + H_{2} O (l) ⇌ H_{3} O^{+} (a q) + C_{2} H_{3} O_{2}^{-} (a q)

H C l + H_{2} O \to H_{3} O^{+} + C l^{-}

H C l

C l^{-}

H_{3} O^{+}

H_{2} O

H_{2} O

H_{3} O^{+}

H C l

H_{3} O^{+}

H_{2} O + H_{2} O ⟶ H_{3} O^{+} + O H^{-}

H C l

H C l (a q) + H_{2} O \to C l^{-} (a q) + H_{3} O^{+}

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