The conjugate base of $H S O_{4}^{-}$ ion is:

S O_{4}^{-}

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S O_{4}^{2 -}

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S O_{4}^{3 -}

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S O_{4}^{4 -}

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Solution

The correct option is A $S O_{4}^{2 -}$
Conjugate base of $H S O_{4}^{-}$
$H S O_{4}^{-} - H^{+} \to S O_{4}^{2 -}$

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