Question

The conjugate of the complex number $\frac{1-i}{1+i}$ is-

Answer 1

$\frac{1-i}{1+i}\times \frac{1-i}{1-i}=\frac{1+i^2-2i}{1-i^2}=\frac{1-1-2i}{1+1}=\frac{2i}{2}=-i$

Conjugate of $0-i$ is $i$