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Question

the constant term in the expansion of (1+x+2x)6

A
581
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B
569
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C
517
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D
479
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Solution

The correct option is A 581
(1+x+2x)66C0(1+x)6+6(1(1+x)5(2x)+6(2(1+x)4(2x)2+6C3(1+x)3(2x)3
Further terms will not be constant
6C06C0+6C155C1(2)+6C24C2(2)2
+6C33C3(2)3
1+60+4(15)6+160=581

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