Question

The construction of triangle ΔA'C'B similar to triangle ΔACB is shown in the figure below. Then

• A. $\angle A^{\prime }B{C}^{\prime }\ne \angle CBA$
• B. $\angle B{A}^{\prime }{C}^{\prime }=\angle BAC$
• C. $\angle CAB=\angle ACB$

Answer 1

The correct option is B $\angle B{A}^{\prime }{C}^{\prime }=\angle BAC$

Since $\Delta ABC\sim \Delta A^{\prime }B{C}^{\prime }$
Hence $\angle B{A}^{\prime }{C}^{\prime }=\angle BAC$
($\because$ corresponding angles of similar triangles are equal.)
All other options do not satisfy the properties of similarity.