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Question

The contents of urn I and II are as follows:
Urn I: 4 white and 5 black balls
Urn II: 3 white and 6 black balls
One urn is chosen at random and a ball is drawn and its colour is noted and replaced back to the urn. Again a ball is drawn from the same urn colour is noted and replaced. The process is repeated 4 times and as a result one ball of white colour and 3 of black colour are noted. Find the probability the chosen urn was I.

A
125287
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B
64127
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C
25287
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D
79192
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Solution

The correct option is A 125287
1971518_296009_ans_f323354a07db4735a73b26040df7e4ed.jpg

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