The contrapositive of (p∨q)⇒r is
The contrapositive of (∼p∧q)→(q ∧∼r) is
Factorise: (p2+q2−r2)2−4p2q2
The dual of statement p∨(q∧r)≡(p∨q)∧(p∨r) is
p3+ q3 + r3 – 3pqr = ?