The converse of the statement "if $p < q$ , then $p - x < q - x$ " is :

p < q

, then

p - x > q - x

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p > q

, then

p - x > q - x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p - x > q - x

, then

p > q

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p - x < q - x

, then

p < q

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Solution

The correct option is D If $p - x < q - x$ , then $p < q$
$\begin{matrix} p < q, t h e n p - x < q - x i s p - x < q - x \end{matrix}$
adding n both sides
$\begin{matrix} p - x + x < q - x + x p < q \end{matrix}$

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The converse of the statement "if p<q, then p−x<q−x" is :

The correct option is D If p−x<q−x, then p<qp<q,thenp−x<q−xisp−x<q−xadding n both sidesp−x+x<q−x+xp<q

The converse of the statement "if $p < q$ , then $p - x < q - x$ " is :

The correct option is D If $p - x < q - x$ , then $p < q$
$\begin{matrix} p < q, t h e n p - x < q - x i s p - x < q - x \end{matrix}$
adding n both sides
$\begin{matrix} p - x + x < q - x + x p < q \end{matrix}$