Question

The conversion $A\to B$ follows second order kinetics. Doubling, the concentration of $A$ will increase the rate of formation of $B$ by a factor of:

• A. 2
• B. 4
• C. 0.5
• D. 0.25

Answer 1

The correct option is B 4

For the second order reaction,

$Rate=k\times [A{]}^2$

if the concentration of $A$ is doubled, then $A$ becomes $2A$ in the rate reaction, which implies,

$Rate=k\times [2A{]}^2$

$\Rightarrow k\times 4\times [A{]}^2$

$\Rightarrow 4\times k\times [A{]}^2$

$\therefore$ the rate of the formation of $B$ increases by a factor of 4