Question

The conversion of A to B follows second order kinetics. Doubling the concentration of A increases the rate of formation of B by a factor of

• A. 2
• B. 4
• C. $\frac{1}{2}$
• D. $\frac{1}{4}$

Answer 1

The correct option is B 4

For a second order kinetics of the reaction A $\to$ B we have rate = $k[A{]}^2$. When conc. of A is doubled the rate of the reaction increases by a factor of $2^2(=4)$. Since rate of conversion of A = rate of formation of B. Hence rate of formation of B also increases 4 times.