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Physical and Chemical Properties of Hydrogen

The conversio...

Question

The conversion of ${C r}_{2} O_{7}^{2 -}$ to ${C r}^{3 +}$ during a chemical reaction is an example of:

hydrolysis

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displacement

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neutralization

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reduction

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oxidation

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Solution

The correct option is D reduction
Loss of electron is oxidation whereas gain of electron is reduction. In the given example cromiun converts from oxidation state $C r^{+ 8}$ in $C r_{2} O_{7}^{2 -}$ to $C r^{+ 3}$ i.e. gain of 5 electrons. Hence it is an example of reduction.

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Similar questions

{C r}_{2} O_{7}^{2 -} H^{+} - - \to {C r}^{3}

E q . w t o f {C r}_{2} O_{7}^{2 -}

{C r}_{2} O_{7}^{2 -}

H N O_{2}

{C r}_{2} O_{7}^{2 -} + 5 H^{+} + 3 H N O_{2} \to 2 {C r}^{3 +} + 3 N {O_{3}}^{-} + 4 H_{2} O

{C r}_{2} {O_{7}}^{2 -}

2.4 \times 10^{- 4}

m o l

L^{- 1}

s^{- 1}

H N O_{2}

{C r}^{3 +}

{C r}_{2} O_{7}^{2 -} + {F e}^{2 +} + H^{\oplus} ⟶ {C r}^{3 +} + {F e}^{3 +} + H_{2} O

6 {F e}^{2 +} + 14 H^{\oplus} + {C r}_{2} O_{7}^{2 -} ⟶ 6 {F e}^{3 +} + 2 {C r}^{3 +} + 7 H_{2} O

{C r}_{2} O_{7}^{2 -} (a q) + H {N O}_{2} (a q) ⟶ {C r}^{3 +} (a q) + {N O}_{3}^{-} (a q)

{C r}_{2} O_{7}^{2 -}

{C r}^{3 +}

{C r}_{2} O_{7}^{2 -} = x \times

x

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