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Second Order Reaction

The conversio...

Question

The conversion of molecule X to Y follow second order kinetics. If the concentration of X is increased to three times then the rate of formation of Y will be:

A

increased by 8 times

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B

increased by 9 times

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C

increased by 6 times

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D

decreased by 8 times

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Solution

The correct option is B increased by 9 times
For 2nd order reaction,
$(R a t e)_{1} = K [X]^{2}$

$(R a t e)_{2} = K [3 X]^{2} = 9 K [X]^{2}$

$(R a t e)_{2} = 9 (R a t e)_{1}$ .

Hence, option B is correct.

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