The conversion of molecules A to B follows second order kinetics. Doubling the concentration of A will increase the rate of formation of B by a factor of
A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
14
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B4 For 2nd order kinetics we have v=k[A]2. When concentration doubles, the velocity increases by 22 times. Hence the answer is 4.