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Question

The conveyor belt is designed to transport packages of various weights. Each 10 kg package has a coefficient of kinetic friction 0.15. If the speed of the conveyor belt is 5m/s, and then it suddenly stops, determine the distance the package will slide before coming to rest:
(g = 9.8m/s2)

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A
8.5 m
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B
8 m
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C
10 m
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D
6 m
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Solution

The correct option is B 8.5 m
The block is initially moving with velocity 5 m/s
when belt stops the friction force retard the motion of block
friction force
F=μmg
F=0.15×10×9.8=14.7N
retardation a =Fm
Fm=μg=1.47
now,
v2=u2+2as0=522×1.47×ss=8.5m

Option A is correct.

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